help me work this out f(x)=x^2-7x+9 x intercepts.
To find the x-intercepts of a function, you need to set the function equal to zero and solve for x. In this case, we need to solve the equation f(x) = 0 for x.
So, let's set the given function equal to zero:
x^2 - 7x + 9 = 0
To solve this quadratic equation, you can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
In our equation, the coefficients are:
a = 1
b = -7
c = 9
Substituting these values into the quadratic formula, we get:
x = (-(-7) ± √((-7)^2 - 4 * 1 * 9)) / (2 * 1)
x = (7 ± √(49 - 36)) / 2
x = (7 ± √13) / 2
So, the x-intercepts are the values of x when f(x) equals zero:
x = (7 + √13) / 2
x = (7 - √13) / 2
Therefore, the x-intercepts of the function f(x) = x^2 - 7x + 9 are (7 + √13) / 2 and (7 - √13) / 2.