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August 30, 2014

August 30, 2014

Posted by **Jason** on Saturday, January 28, 2012 at 11:10am.

- statisticas -
**PsyDAG**, Saturday, January 28, 2012 at 12:42pmFind table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion (.41 between score and mean) for Z score.

82% = mean ± 1.34 SEm

SEm = SD/√n

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