Two blocks, the first with a mass of 30 kg, and the second 10kg, are connected by a string and pulled accross a frictionless surface by a force with a magnitude of 75 N. Find the magnitude of the tension acting along the string that connects them.

Which block is being pulled by the string?

First, get the accleration rate of both using

F = 75 N = (30 + 10)*a

Use that acceleration rate to get the tensjon in the string.

I don't know please help

To find the magnitude of the tension acting along the string, we need to consider the forces acting on both blocks.

First, let's denote the acceleration of the system as "a".

For the first block (30 kg):
- The force acting on it is the tension force.
- The mass is 30 kg.
- The acceleration is "a".
- Therefore, the tension force is given by T1 = m1 * a, where m1 is the mass of the first block.

For the second block (10 kg):
- The force acting on it is the tension force.
- The mass is 10 kg.
- The acceleration is "a".
- Therefore, the tension force is given by T2 = m2 * a, where m2 is the mass of the second block.

Since the two blocks are connected by a string, the magnitude of the tension force acting on both blocks should be the same. Therefore, T1 = T2.

Furthermore, the net external force acting on the system is the applied force (75 N) that is pulling the blocks across the frictionless surface. This force is responsible for the acceleration of the system.

So, we can set up the following equation based on Newton's second law:

Net force = T1 + T2 = (m1 + m2) * a

Substituting the given values:
75 N = (30 kg + 10 kg) * a
75 N = 40 kg * a

Now, we solve for the acceleration "a":
a = 75 N / 40 kg
a ≈ 1.875 m/s²

Finally, we can use this acceleration to find the magnitude of the tension force:
T1 = m1 * a = 30 kg * 1.875 m/s²
T1 ≈ 56.25 N

Therefore, the magnitude of the tension acting along the string that connects the two blocks is approximately 56.25 N.