Homework Help: Physics

Posted by Sejul on Friday, January 27, 2012 at 9:01pm.

A 3.70kg box is sliding across the horizontal floor of an elevator.
The coefficient of kinetic friction between the box and the floor is 0.470.
Determine the kinetic frictional force that acts on the box when
(a) The elevator is stationary.

(b) The elevator is accelerating upward with an acceleration whose magnitude is 2.90 m/s2.

(c) The elevator is accelerating downward with an acceleration whose magnitude is 2.90 m/s2

Physics - Henry, Sunday, January 29, 2012 at 12:08pm
Wb = 3.70 kg * 9.8 N./kg = 36.3 N. =
Weight of box.

Fb = 36.3 N. @ 0 Deg. = Force of box.
Fp = 36.3*sin(0) = 0. = Force Parallel
to floor.
Fv = 36.3*cos(0) = 36.3 N. = Force perpendicular to floor.

a. Fk = u*Fv = 0.470 * 36.3 = 17.1 N.=
Force of kinetidc friction.

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