Suppose you dump a 5-lb sack of sugar into Bellingham Bay.

Assume the sugar disperses uniformly throughout all of the world’s oceans.

Estimate how many molecules of sucrose would be found in each liter of sea water.

See your post above.

To estimate the number of molecules of sucrose in each liter of seawater, we first need to know the molar mass of sucrose (C12H22O11). The molar mass of carbon (C) is 12.01 g/mol, the molar mass of hydrogen (H) is 1.01 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol. Therefore, the molar mass of sucrose is calculated as follows:

Molar mass of sucrose = (12.01 x 12) + (1.01 x 22) + (16.00 x 11) g/mol
= 144.13 + 22.22 + 176.00 g/mol
= 342.35 g/mol

Next, we need to determine the number of moles of sucrose in a 5-lb (pound) sack. Since 1 lb is equal to 0.4536 kg, the mass of the sack is calculated as:

Mass of the sack = 5 lb x 0.4536 kg/lb
≈ 2.268 kg

Now, we can calculate the number of moles of sucrose in the sack using its molar mass:

Number of moles of sucrose = Mass of the sack / Molar mass of sucrose
= 2.268 kg / (342.35 g/mol)
≈ 0.00663 mol

Assuming that the sugar disperses uniformly throughout all of the world’s oceans, which has an estimated volume of about 1.332 billion cubic kilometers or 1.332 x 10^21 liters, we can estimate the number of molecules of sucrose in each liter of seawater:

Number of molecules of sucrose in each liter of seawater = Number of moles of sucrose / Volume of seawater
= 0.00663 mol / (1.332 x 10^21 L)
≈ 4.97 x 10^-24 molecules

Therefore, there would be approximately 4.97 x 10^-24 molecules of sucrose in each liter of seawater.