algebra
posted by poi on .
a cannonaball is fired stright up into the air at a speed of 80 ft/sec from a height of 2ft. A. when will the cannon ball be 98 ft in the air?
B. when will the cannonball hit the ground?

Vi = + 80
g = 32 ft/s^2 (old text, have not seen these units for years)
h = 2 + Vi t  (32/2) t^2
98 = 2 + 80 t  16 t^2
16 t^2  80 t + 96 = 0
t^2  5 t + 6 = 0
(t2)(t3) = 0
t = 2 or 3 seconds
Two on the way up, three on the way down
When will h = 0 ?
0 = 2 + 80 t  16 t^2
8 t^2  40 t 2 = 0
t = [ 40 +/ sqrt(1600 +64) ]/ 16
t = [ 40 +/ 40.8 ] / 16
negative time was before we pulled the trigger, use + solution
t = 80.8/16 = 5.05 seconds