The hypotenuse of a right triangle is 8cm and one leg is 6cm. Find the length of the other leg. How did my teacher end up with 2 x square root of 7?

Pythagorean theorem.

hyp.^2 = side^2 + side^2

8^2 = 6^2 + x^2

Solve for x.

a right triangle find the value with 71 5 find x n y answers

To find the length of the other leg of a right triangle given the hypotenuse and one leg, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

Let's denote the length of the other leg as "x". According to the Pythagorean theorem, we have the following equation:

x^2 + 6^2 = 8^2

Simplifying this equation, we get:

x^2 + 36 = 64

Next, we can subtract 36 from both sides of the equation:

x^2 = 64 - 36
x^2 = 28

To solve for x, we need to find the square root of both sides:

√(x^2) = √28

This can be simplified as:

x = √28

So, the length of the other leg is the square root of 28. To further simplify this, we can express it as the product of two square roots:

x = √(4 * 7)

Since 4 is a perfect square, we can simplify further:

x = 2√7

Hence, your teacher ended up with 2√7 as the length of the other leg, which is the simplified form of the square root of 28.