What is the full balanced equation??

Hg2(NO3)2(aq) + HBr(aq) → ?

Hg2(NO3)2(aq) + 2HBr(aq) ==> Hg2Br2(s) + 2HNO3(aq)

Hg(I) salts commonly dimerize and instead of existing as HgCl or HgBr or HgI they exist as Hg2Cl2, Hg2Br2, and Hg2I2.

To determine the full balanced equation, we need to combine the elements and ensure that the total number of atoms on both sides of the equation is equal. Here are the steps to balance the equation:

Step 1: Write the given unbalanced equation:
Hg2(NO3)2(aq) + HBr(aq) → ?

Step 2: Split the chemical formulas into their individual ions:
Hg2(NO3)2 -> Hg2^2+(aq) + 2NO3^-(aq)
HBr -> H+(aq) + Br^-(aq)

Step 3: Write the balanced equation by combining the ions:
Hg2^2+(aq) + 2NO3^-(aq) + H+(aq) + Br^-(aq) → ?

Step 4: Balance the atoms:
In this case, both sides of the equation are balanced in terms of the number of each type of atom. However, to maintain electrochemical neutrality, we need to balance the charges by adding electrons. The mercury (Hg) in solution tends to displace the hydrogen (H+), leading to the formation of elemental mercury, Hg, and water, H2O.

Therefore, the balanced equation would be:
Hg2^2+(aq) + 2NO3^-(aq) + 2H+(aq) + 2Br^-(aq) → Hg(l) + 2NO3^-(aq) + H2O(l) + 2Br^-(aq)

The final equation represents the reaction between Hg2(NO3)2(aq) and HBr(aq), yielding liquid mercury (Hg), nitrate ions (NO3^-), water (H2O), and bromide ions (Br^-).

To determine the balanced equation for the reaction between Hg2(NO3)2(aq) and HBr(aq), we need to consider the elements involved and balance them.

First, let's break down the compounds into their respective ions:

Hg2(NO3)2(aq) → Hg2 2+ (aq) + 2 NO3 - (aq)
HBr(aq) → H+ (aq) + Br- (aq)

Now, let's balance the equation:

Hg2(NO3)2(aq) + 2 HBr(aq) → Hg2Br2(s) + 2 HNO3(aq)

The balanced equation for the reaction between Hg2(NO3)2(aq) and HBr(aq) is:

Hg2(NO3)2(aq) + 2 HBr(aq) → Hg2Br2(s) + 2 HNO3(aq)