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January 28, 2015

January 28, 2015

Posted by **Mi26** on Thursday, January 26, 2012 at 4:10pm.

- physics -
**Henry**, Saturday, January 28, 2012 at 4:08pmd1 + d2 = 93 m.

0.5a1*t^2 + 0.5a2*t^2 = 93,

0.11*t^2 + 0.17*t^2 = 93,

0.28t^2 = 93,

t^2 = 332.1,

t = 18.2 s. = Time elapsed before collision,

d1 = 0.11*(18.2)^2 = 36.4 m.= Distance

from Sir George's starting point.

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