Posted by **Anonymous** on Thursday, January 26, 2012 at 3:51pm.

Vector Barrowbold has magnitude 9.4 and direction 14° below the +x-axis. Vector Carrowbold has x-component Cx = -1.6 and y-component Cy = -7.7.

Compute direction of Carrowbold & direction of Carrowbold + Barrowbold.

Also direction of Carrowbold − Barrowbold and direction in ° counter-clockwise from the +x-axis!

Thnk you

- Physics -
**Henry**, Friday, January 27, 2012 at 8:42pm
C = -1.6 - i7.7. Q3.

tanAr = Y/X = -7.7 / -1.6 = 4.8125,

Ar = 78.3 Deg. =Reference angle.

A = 180 + Ar = 180 + 78.3 = 258.3 Deg.

B = 9.4 @ (-14) Deg. C = -1.6 -i7.7.

X = 9.4*cos(-)14 + (-1.6) = 7.52.

Y = 9.4*sin(-14) + (-7.7) = -9.97.

tanAr = Y/x = -9.97 / 7.52 = -1.3263,

Ar = -53 Deg.

A = -53 + 360 = 307 Deg.

C = -1.6 -i7.7. B = 9.4 @(-14) Deg.

X = -1.6 - 9.4*cos(-14) = -10.72.

Y = -7.7 - 9.4*sin(-14) = -5.43.

tanAr = Y/X = -5.43 / -10.72 = 0.5062.

Ar = 26.8 Deg.

A = 180 + 26.8 = 206.8 Deg.

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