Posted by Anonymous on .
Vector Barrowbold has magnitude 9.4 and direction 14° below the +xaxis. Vector Carrowbold has xcomponent Cx = 1.6 and ycomponent Cy = 7.7.
Compute direction of Carrowbold & direction of Carrowbold + Barrowbold.
Also direction of Carrowbold − Barrowbold and direction in ° counterclockwise from the +xaxis!
Thnk you

Physics 
Henry,
C = 1.6  i7.7. Q3.
tanAr = Y/X = 7.7 / 1.6 = 4.8125,
Ar = 78.3 Deg. =Reference angle.
A = 180 + Ar = 180 + 78.3 = 258.3 Deg.
B = 9.4 @ (14) Deg. C = 1.6 i7.7.
X = 9.4*cos()14 + (1.6) = 7.52.
Y = 9.4*sin(14) + (7.7) = 9.97.
tanAr = Y/x = 9.97 / 7.52 = 1.3263,
Ar = 53 Deg.
A = 53 + 360 = 307 Deg.
C = 1.6 i7.7. B = 9.4 @(14) Deg.
X = 1.6  9.4*cos(14) = 10.72.
Y = 7.7  9.4*sin(14) = 5.43.
tanAr = Y/X = 5.43 / 10.72 = 0.5062.
Ar = 26.8 Deg.
A = 180 + 26.8 = 206.8 Deg.