Posted by d-boe on Thursday, January 26, 2012 at 3:49pm.
a rhombus is a a quad with 4 equal sides.
So if you have followed the convention of naming the vertices in either a clockwise or couter-clockwise fashion, then both GH and JH are sides of the rhombus
so 5x-2 = x+9
4x = 11
x = 11/4 = 2.75
The fact that the diagonals intersect at C appears redundant information.
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