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September 1, 2014

September 1, 2014

Posted by **d-boe** on Thursday, January 26, 2012 at 3:49pm.

- geometry -
**Reiny**, Thursday, January 26, 2012 at 5:04pma rhombus is a a quad with 4 equal sides.

So if you have followed the convention of naming the vertices in either a clockwise or couter-clockwise fashion, then both GH and JH are sides of the rhombus

so 5x-2 = x+9

4x = 11

x = 11/4 = 2.75

The fact that the diagonals intersect at C appears redundant information.

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