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July 30, 2014

July 30, 2014

Posted by **Anonymous** on Thursday, January 26, 2012 at 10:41am.

My attempted solution:

.042^(1/3) = .3476 m for the area

.042^(2/3) = .1208 m for the area of a side

(273 + 195)/(273+20) = 1.597

1.597 * .1208 = .19292

.19292 was my answer.

Did I not take this far enough or is the entire set-up wrong?

- Physics -
**drwls**, Thursday, January 26, 2012 at 11:25amVolume = 4.2*10^-2 m^3

Side length is the cube root of that:

a = 0.34760 m

Side area = a^2 = 0.1208 m^2

Absolute Temperature ratio = 1.5973

New atmospheric pressure

= 1.5973*1.013*10^5 N/m^2

= 1.618*10^5 N/m^2

Multiply that by the area of a side.

Your only mistake was not converting pressure from atmospheres to Pascals (N/m^2)

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