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September 1, 2014

September 1, 2014

Posted by **Heather P.** on Thursday, January 26, 2012 at 1:08am.

- Math -
**Reiny**, Thursday, January 26, 2012 at 9:29amUsing Venn diagram, start filling in the information

Put 5 in the intersection of all three

C+T --> 8, but we have already accounted for 5 of those, so put 3 into the intersection of only C and T

only S --> 3, so put 3 into S which is not part of any intersection

C+S --> 8 , but we have already accounted for 5 of those, so put 3 into the intersection of only C and S

the whole C circle is 13 , but 3+3+5 or 11 are already counted, so the only C part is 2

We don't know what only S and T is, call it x

For S, x+5+3+3=14

x = 3

For T, we already have 11, but the total of T is 13

so we would need 2 for "only T" part.

Complete C the same way, I get 2 for the "only C" part

Now add up all the components,

for a total of 21 sandwiches

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