Wednesday

July 23, 2014

July 23, 2014

Posted by **Kenneth** on Wednesday, January 25, 2012 at 11:46pm.

Solve:

(3x^-1 y^-2)^-2 (x^2 y^5)^-1

[[Spaces denote the end of the exponent.]]

Because of the law of exponents that deals with negative exponents, I did the reciprocal and distributed the exponent, getting (1/3x^2 y^4) for the first part of the problem. In the second part, I got (1/x^2 y^5).

Combining exponents, my final answer was: 1/3x^4 y^9, which is not a correct answer.

Can someone help me? Thank you!

- Algebra II -
**ana**, Thursday, March 8, 2012 at 3:33pm-12+4x/4

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