Please help me with the following problem, I have submitted the answer: 88.2 and was told that it was incorrect. The word problem reads:
If you do not consider air resistance, gravity causes a falling object to descend a distance of (9.8)t2 where t is the time in seconds. If a 16 pound bowling ball is dropped from the tallest building in the world, how many meters does it fall during the 4th and 5th seconds combined
Thank you
Your equation is wrong
d = (1/2) 9.8 t^2 you forgot the 1/2
d = 4.9 t^2
after three seconds it has fallen
4.9 (9) = 44.1 m
after five seconds it has fallen
4.9 (25) = 122.5
122.5 - 44.1 = 78.4 meters
To solve this problem, we can use the formula given in the problem, which states that the distance a falling object travels under the influence of gravity is (9.8)t^2, where t is the time in seconds.
To find the total distance the bowling ball falls during the 4th and 5th seconds combined, we need to subtract the distance it falls during the first 3 seconds from the distance it falls during the first 5 seconds.
To find the distance during the first 3 seconds, we can substitute t=3 into the formula.
Distance during the first 3 seconds = (9.8) * (3^2) = (9.8) * (9) = 88.2 meters.
Next, to find the distance during the first 5 seconds, we can substitute t=5 into the formula.
Distance during the first 5 seconds = (9.8) * (5^2) = (9.8) * (25) = 245 meters.
Finally, to find the total distance the bowling ball falls during the 4th and 5th seconds combined, we need to subtract the distance during the first 3 seconds from the distance during the first 5 seconds.
Total distance during the 4th and 5th seconds = Distance during the first 5 seconds - Distance during the first 3 seconds = 245 meters - 88.2 meters = 156.8 meters.
Therefore, the correct answer is 156.8 meters, not 88.2 meters.