Posted by Jake on Wednesday, January 25, 2012 at 10:06pm.
How many solutions does the equation cosx + 1/2 = 1 have for 0<x<2pi
cosx+1/2=1
cosx+1=2
cosx=21
cosx=1
therefore 1 solution?
A) 1
b) 2
c) 3
d) 4

Math  Reiny, Wednesday, January 25, 2012 at 10:54pm
What did you do ????
cosx + 1/2 = 1
cosx = 1/2
the cosine is positive in quads I and IV
x = 30° or x = 330° or (π/6 and 11π/6)
so obviously 2 solutions between 0 and 2π

Math  Jake, Wednesday, January 25, 2012 at 11:08pm
How come I am not suppose to get rid of the the denominator?

Math  Reiny, Thursday, January 26, 2012 at 8:30am
if you had multiplied by 2 then your second line should have been
2cosx + 1 = 2 . and then
2cosx = 1
cosx = 1/2 , now pick it up in my solution.
you forgot to multiply the cosx by 2
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