Wednesday

April 23, 2014

April 23, 2014

Posted by **Anonymous** on Wednesday, January 25, 2012 at 9:36pm.

lim x->0 [ln(1+x)]/[x] = 1

- college calculus -
**Damon**, Wednesday, January 25, 2012 at 9:45pm[ln (u + h) - ln (u)]/h as h-->0= definition of d/du(ln u) = 1/u

here u = 1

so

1/1 = 1

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