Posted by **Jake** on Wednesday, January 25, 2012 at 9:09pm.

Solve (sinx-1)(cosx -1/2) = 0 where 0≤x<2pi

a) pi/3, pi/2, 5pi/3

b) pi/6, 5pi/6, pi

c) pi/3, pi, 5pi/3

d) pi/6, pi/2, 5pi/6

## Answer this Question

## Related Questions

- Pre-Cal(Please check) - Approximate the equation's solutions in the interval (0,...
- Calculus - Find the area in the first quadrant bounded by the arc of the circle ...
- PreCalculus - Hi I need some assistance on this problem find the exact value do ...
- trig - using the fact that 5pi/8=1/2(5pi/8) and the half angle identity for cos ...
- Trig - can you please simplify these in faction form? (pi/3) +1=? (2pi/3) +1=? (...
- Calculus - Find the area under one arch of a cycloid describe by the parametric ...
- Alg. II - Solve y=Arcsin 1/2 A.) -5pi/6 B.) 5pi/6 C.) -pi/6 D.) pi/6
- maths - hey, i would really appreciate some help solving for x when: sin2x=cosx ...
- MATH - 2tan^2x-tanx-1=0 0<x<2pi •MATH - Steve, Thursday, July 18, 2013 at ...
- check math - Here are my answers. Can you check if I got the right answers? ...