posted by Nita on .
An aqueous solution of calcium chloride boils at 101.3. How many kilograms of calcium chloride were dissolved in 1000 g of the solvent?
CaCl2 is three particles per molecule.
solve for molality, then
molality= moles/1000 solve for moles, then finally,grams of CaCl2 from moles, then divide by 1000 to get kg