Posted by **Angel** on Wednesday, January 25, 2012 at 8:31pm.

The specific heat of mercury is .03cal/g*C, and it's boiling point is 357*C. The specific heat of water is 1 cal/g*C. It takes 65 calories of energy to vaporize one gram of mercury and 540 calories to vaporize one gram of water. If both substances begin at about 22*C does it take more energy to boil a gram of mercury or a gram of water? If someone can give me the formula to use, I can try to figure it out myself! Thanks

- physics -
**bobpursley**, Wednesday, January 25, 2012 at 8:36pm
heat to boil 1 gram water:

mcdeltaT+ Lv*m

1*1*(100-22)+540*1

heat to boil 1 gram Hg

mcdeltatT+Lv*m

1*.03(357-22)+65*1

do the math.

- physics -
**drwls**, Wednesday, January 25, 2012 at 8:41pm
Energy required per gram =

Q = (heat of vaporization) + (Tboiling - Tinitial)*(specific heat)

Compute and compare that quantity for both liquids.

For mercury,

Q = 65 + 335*0.03

For water

Q = 540 + 78*1.0

Water's heat requirement is much higher

## Answer This Question

## Related Questions

- Science -- Check my Answer Plz - How much heat (calories) must be applied to a ...
- Physics - You and another person go to the museum and decide to take a look at ...
- science - The latent heat of vaporization of water is 540 calories/gram. How ...
- IPC - The latent heat of vaporization of water is 540 calories/gram. How many ...
- 11th grade - The latent heat of vaporization of water is 540 calories/gram. How ...
- Physics - How much heat is required to melt 50 g of mercury at -45 degrees ...
- Physics - How much heat is required to melt 50 g of mercury at -45 degrees ...
- Physics - How much heat is required to melt 50 g of mercury at -45 degrees ...
- IPC-Science - The specific heat of gold is 0.031 calories/gramĀ°C. If 10.0 grams ...
- physics - how much heat is required to vaporize 7 grams of ice initially at 0 ...

More Related Questions