Posted by Angel on .
The specific heat of mercury is .03cal/g*C, and it's boiling point is 357*C. The specific heat of water is 1 cal/g*C. It takes 65 calories of energy to vaporize one gram of mercury and 540 calories to vaporize one gram of water. If both substances begin at about 22*C does it take more energy to boil a gram of mercury or a gram of water? If someone can give me the formula to use, I can try to figure it out myself! Thanks
heat to boil 1 gram water:
heat to boil 1 gram Hg
do the math.
Energy required per gram =
Q = (heat of vaporization) + (Tboiling - Tinitial)*(specific heat)
Compute and compare that quantity for both liquids.
Q = 65 + 335*0.03
Q = 540 + 78*1.0
Water's heat requirement is much higher