Posted by Annie on Wednesday, January 25, 2012 at 7:44pm.
to have two zeros, either real or complex,
b^2 - 4ac ≠ 0
4x^2 + x(2k - 3) + 1
discrim. = (2k-3)^2 - 4(4)(1)
= 4k^2 - 12k + 9 - 16
= 4k^2 - 12k - 7
to have only 1 root
4k^2 - 12k - 7 = 0
(2k - 7)(2k + 1) = 0
k = 7/2 or k = -1
So to have two roots, k ≠ 7/2 or k ≠ -1
So put any value of k other than those two and you will get 2 differentroots.
Related Questions
math - Determine the values of k for which the function f(x)= 4x^2-3x+2kx+1 has ...
math - Determine the values of k for which the function f(x)=4x^2-3x+2kx+1 has ...
math grade 11 - I need help with this question determine the values in k for ...
math grade 11 - I need help with this question determine the values in k for ...
Math - For what values of k will the functon f(x)=kx^2-4x+k have no zeros ...
Math - Determine the values of k for which the function f(x)=4x^2-3x+2kx+1 has 2...
math grade 11 - Determine the value of k for which the function f(x)= 4x^2- 3x+...
Math - For what values of k does the function f(x)=(k+1)x^2+2kx+k-1 have no ...
Math( help please ! ) - For what values of k will the function f(x)=3x^2+4x+k=0 ...
Math - determine the value of k for which the fuction f(x)=4x^2-3x+2kx+1 has 2 ...
For Further Reading
