Saturday

August 23, 2014

August 23, 2014

Posted by **Annie** on Wednesday, January 25, 2012 at 7:44pm.

- math -
**Reiny**, Wednesday, January 25, 2012 at 10:17pmto have two zeros, either real or complex,

b^2 - 4ac ≠ 0

4x^2 + x(2k - 3) + 1

discrim. = (2k-3)^2 - 4(4)(1)

= 4k^2 - 12k + 9 - 16

= 4k^2 - 12k - 7

to have only 1 root

4k^2 - 12k - 7 = 0

(2k - 7)(2k + 1) = 0

k = 7/2 or k = -1

So to have two roots, k ≠ 7/2 or k ≠ -1

So put any value of k other than those two and you will get 2 differentroots.

**Related Questions**

math - Determine the values of k for which the function f(x)= 4x^2-3x+2kx+1 has ...

math grade 11 - I need help with this question determine the values in k for ...

math grade 11 - I need help with this question determine the values in k for ...

math - Determine the values of k for which the function f(x)=4x^2-3x+2kx+1 has ...

math grade 11 - Determine the value of k for which the function f(x)= 4x^2- 3x+...

Math - For what values of k will the functon f(x)=kx^2-4x+k have no zeros ...

Math - Determine the values of k for which the function f(x)=4x^2-3x+2kx+1 has 2...

Math - For what values of k does the function f(x)=(k+1)x^2+2kx+k-1 have no ...

Math - Q.1)If one zero of the polynomial 3x2-kx-2 is 2 find the other zero.allso...

Algebra - Complete the table for each function. 1. f(x) = √x The x values ...