Please help me with the following problem, I have veiwed the answers to the other problems like this one and were told they were incorrect: If you do not consider air resistance, gravity causes a falling object to descend a distance of (9.8)t2 where t is the time in seconds. If a 16 pound bowling ball is dropped from the tallest building in the world, how many meters does it fall during the 4th and 5th seconds combined.

To find the distance the bowling ball falls during the 4th and 5th seconds combined, we can use the given formula: distance = (9.8)t^2, where t is the time in seconds.

First, let's calculate the distance fallen during the 4th second. Substitute t = 4 into the formula:
distance in 4th second = (9.8) * (4)^2

Simplifying the equation,
distance in 4th second = (9.8) * 16 = 156.8 meters

Next, let's calculate the distance fallen during the 5th second. Substitute t = 5 into the formula:
distance in 5th second = (9.8) * (5)^2

Simplifying the equation,
distance in 5th second = (9.8) * 25 = 245 meters

Now, to find the total distance fallen during the 4th and 5th seconds combined, we add the distances calculated above:
total distance = distance in 4th second + distance in 5th second
total distance = 156.8 + 245 = 401.8 meters

Therefore, the bowling ball falls a total of 401.8 meters during the 4th and 5th seconds combined.