You provide the manager with a quadratic equation that models the expected number of ticket sales for each day x.
(x = 1 is the day tickets go on sale).
Tickets = -0.6x2 + 12x + 11 .
Describe what happens to the ticket sales as time passes. My question is sinc the coefficient is negative and you graph downward the ticket sales would low? Please help
well, sort of ....
the number of ticket sales will increase until the maximum is reached, after that the ticket sales will decrease.
for any function
f(x) = ax^2 + bx + c, the max/min of the function is obtained when x = -b/(2a)
in your case
x = -12/(2(-.6)) = 10
when x = 10, tickets sales = -.6(100) + 12(10) + 11 = 71
I will leave it up to you to show that the sales are less for both x= 9 and x=11
Thanks for helping me solve this problem!
To understand what happens to ticket sales as time passes, we can analyze the coefficient of the quadratic term (-0.6x^2) in the equation.
In a quadratic equation of the form y = ax^2 + bx + c, the coefficient "a" determines the shape of the graph. If "a" is positive, the graph opens upwards, indicating a positive relationship between x and y. In this case, as x increases, the ticket sales would also increase.
However, if "a" is negative, as in the equation given (-0.6x^2), the graph opens downwards, indicating a negative relationship between x and y. In this scenario, as x increases, the ticket sales would actually decrease.
So, based on the given quadratic equation, as time passes (x increases), the ticket sales would indeed decrease since the coefficient is negative and the graph opens downward.