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It takes 208.4 kJ of energy to remove one mol of electrons from the atoms on the surface of rubidium metal. If rubidium metal metal is irradiated with 254-nm light, what is the maximum kinetic energy the released electrons can have?

  • Chemistry -

    208,400 J/mol x (1/6.02E23) = ? work function.
    E of photon = hc/wavlength = 6.626E-34*3E8/254E-9 = x

    Take the difference between x and ? above and that is the maximum energy of an ejected electron which is KE = 1/2 mv2. Then solve for v in m/s.

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