Chemistry
posted by Kaleen on .
It takes 208.4 kJ of energy to remove one mol of electrons from the atoms on the surface of rubidium metal. If rubidium metal metal is irradiated with 254nm light, what is the maximum kinetic energy the released electrons can have?

208,400 J/mol x (1/6.02E23) = ? work function.
E of photon = hc/wavlength = 6.626E34*3E8/254E9 = x
Take the difference between x and ? above and that is the maximum energy of an ejected electron which is KE = 1/2 mv^{2}. Then solve for v in m/s.