Posted by Martha on .
treatment of a 0.3203g sample of impure soduim chloride with an excess of AgNo3 resulted in the formation of 0.7331g of AgCl.
how many grams of sodium chloride were in the sample?
What is the weight percentage of NaCl in the sample?
Convert 0.7331 g AgCl to g NaCl. The easy way to do that is
0.7331 x (molar mass NaCl/molar mass AgCl) = ?
Then %NaCl = (g NaCl/g sample) x 100 = ??