Posted by Ali on Tuesday, January 24, 2012 at 11:46am.
A stone is launched straight up by a slingshot. Its initial speed is 20.1 m/s and the stone is 1.30 m above the ground when launched. Assume g = 9.80 m/s2.
(a) How high above the ground does the stone rise?
(b) How much time elapses before the stone hits the ground?

physics  Henry, Thursday, January 26, 2012 at 5:14pm
a. hmax = ho + (Vf^2Vo^2 / 2g.
hmax=1.3 +(0(20.1)^2 / 19.6=21.9 m.
b. Tr = VfVo) / g,
Tr = (020.1) / 9.8 = 2.05 s. = Rise
time or time to reach max ht.
h = Vo*t + 0.5g*t^2 = 21.9 m.
0 + 4.9t^2 = 21.9,
t^2 = 4.47,
Tf = 2.11 s.Time to fall to ground.
Tr + Tf = 2.05 + 2.11 = 4.16 s. = Time
in flight.
Answer This Question
Related Questions
 physics  A stone is launched straight up by a slingshot. Its initial speed is ...
 Physics  A stone is launched straight up by a slingshot. Its initial speed is ...
 Physics  A stone is dropped from rest from the roof of a 100m high building; 2...
 physics  a stone is thrown straight up from a 50m high building and hits the ...
 Math  A stone is thrown vertically upwards from a platform 60meters above the ...
 physics/calculus  A stone is thrown straight up from the edge of a roof, 600 ...
 physics  A stone with a weight of 5.38 N is launched vertically from ground ...
 Physics  While standing on a bridge 45.0 m above ground, you drop a stone from ...
 Physics  While standing on a bridge 45.0 m above ground, you drop a stone from ...
 physics  While standing on a bridge 45.0 m above ground, you drop a stone from ...
More Related Questions