Posted by Priya on .
the points M(6,8) and E(8,6) are on a circle with radius 10 units. Determine the equation of the line equidistant from points M and E

analytical geometry 
Steve,
what does the circle have to do with it?
The midpoint of ME is (7,1)
The slope of ME is 14/2 = 7
The slope of the perpendicular bisector of ME is thus 1/7
The line is thus
(y+1)/(x7) = 1/7
y = x/7
Makes sense, since the circle is x^2 + y^2 = 100, and the perpendicular bisector of ME must pass through the center of the circle, or (0,0).