Posted by **Priya** on Tuesday, January 24, 2012 at 11:33am.

the points M(6,-8) and E(8,6) are on a circle with radius 10 units. Determine the equation of the line equidistant from points M and E

- analytical geometry -
**Steve**, Tuesday, January 24, 2012 at 1:10pm
what does the circle have to do with it?

The midpoint of ME is (7,-1)

The slope of ME is 14/2 = 7

The slope of the perpendicular bisector of ME is thus -1/7

The line is thus

(y+1)/(x-7) = -1/7

y = -x/7

Makes sense, since the circle is x^2 + y^2 = 100, and the perpendicular bisector of ME must pass through the center of the circle, or (0,0).

## Answer This Question

## Related Questions

- maths pleaaaase - The point X and Y are 8cm apart Draw a scale drawing of the ...
- analytical geometry - Determine the value of p if A(-3;p) is equidistant from ...
- geometry - find the equation of the line that describes all points equidistant ...
- math - the number of noncollinear points needed to determine a circle Two. The ...
- geometry - find the coordinates of the points which are simultaneously 6 units ...
- geometry - find the coordinates of the points which are simultaneously 6 units ...
- Geometry - Which one of these is NOT a step used when constructing an inscribed ...
- math - X1, X2,...,X9 are nine points on the circumference of circle O. Line ...
- Math - A line 'l' intersects line 'm' at point A at 45 degree angle. B and C are...
- Math (urgent) - the equation x^2+y^=25 describes a circle with center at the ...

More Related Questions