A uniform electric field of magnitude 2.70×10^4 N/C makes an angle of 37 degrees with a plane surface of area 1.60×10^−2 m^2 .
What is the electric flux through this surface?
(E-field)*(Area)*sin37
To find the electric flux through a surface, we can use the formula:
Electric Flux = Electric Field * Area * cos(theta),
where:
- Electric Field is the magnitude of the electric field,
- Area is the surface area, and
- theta is the angle between the electric field lines and the surface normal.
In this case, the given information is:
- Electric Field = 2.70×10^4 N/C,
- Area = 1.60×10^−2 m^2, and
- theta = 37 degrees.
Now we can substitute these values into the formula to calculate the electric flux:
Electric Flux = (2.70×10^4 N/C) * (1.60×10^−2 m^2) * cos(37 degrees).
To find cos(37 degrees), we can use a scientific calculator or table. The cosine of 37 degrees is approximately 0.7986.
Electric Flux = (2.70×10^4 N/C) * (1.60×10^−2 m^2) * 0.7986.
Now we can calculate the product:
Electric Flux = (2.70×10^4 N/C) * (1.60×10^−2 m^2) * 0.7986.
Electric Flux = 2.58752 N·m^2/C.
Therefore, the electric flux through the given surface is approximately 2.58752 N·m^2/C.