Posted by Challenge Problem Math Help Please on Monday, January 23, 2012 at 10:32pm.
distance = 9.8t^2
when t=5
distance = 9.8(25) = 245 m
when t=4
distance = 9.8(16) = 156.8
so in the time from 4 seconds to 5 seconds it fell
245-156.8 or 88.2 m
since we are ignoring air resistance, the fact that the ball has a weight of 16 lbs is irrelevant.
what about during the 4th second?
"how many meters does it fall during the 4th and 5th seconds combined"
I saw that Steve.
It did not seem to make a lot of sense to find the total distance of the 4th and 5th second distances.
So I assumed there was a typo and that the question followed the more traditional wording of that type.
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