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Posted by on Monday, January 23, 2012 at 10:32pm.

I have no idea on how to get started.

If you do not consider air resistance, gravity causes a falling object to descend a distance of (9.8)t2 where t is the time in seconds. If a 16 pound bowling ball is dropped from the tallest building in the world, how many meters does it fall during the 4th and 5th seconds combined.
Thank you

  • MATH - , Monday, January 23, 2012 at 10:55pm

    distance = 9.8t^2

    when t=5
    distance = 9.8(25) = 245 m
    when t=4
    distance = 9.8(16) = 156.8

    so in the time from 4 seconds to 5 seconds it fell
    245-156.8 or 88.2 m

    since we are ignoring air resistance, the fact that the ball has a weight of 16 lbs is irrelevant.

  • MATH - , Tuesday, January 24, 2012 at 4:41am

    what about during the 4th second?

    "how many meters does it fall during the 4th and 5th seconds combined"

  • MATH - , Tuesday, January 24, 2012 at 8:03am

    I saw that Steve.
    It did not seem to make a lot of sense to find the total distance of the 4th and 5th second distances.
    So I assumed there was a typo and that the question followed the more traditional wording of that type.

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