Posted by Armun on Monday, January 23, 2012 at 8:43pm.
the vertex is at (214.26,102.51)
So, y = C(x-214.26)^2 + k
102.51 = C(0)^2 + k
so, k = 102.51
y = C(x-214.26)^2 + 102.51
0 = C(432-214.26)^2 + 102.51
C = -0.002162
y = -0.002162(x-214.26)^2 + 102.51
y = -.002162x^2 + .92646x + 3.25831
y = -.002162(x+3.4885)(x-432)
Why are these poor models for a parabola, Where a ball starts a a certain point and then is hit to reach a maximum height (vertex) and then lands at a certain point
i. y = -0.002x(x - 437.1)
ii. y = -0.5x + 216x + 3
iii. y = -0.002x + 0.879x + 3.981
iv. y = -0.002x + 0.8732x - 3.981
Thanks!
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