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January 31, 2015

January 31, 2015

Posted by **Armun** on Monday, January 23, 2012 at 8:43pm.

Suppose the ball was 3.24 feet above ground when it was hit, and that it reached a maximum height of approximately 102.51 feet when it had traveled a ground distance of approximately 214.26 feet. The ball lands after traveling a ground distance of approximately 432 feet.

Find an equation of the form y = C(x-z1)(x-z2) where z1 and z2 are the zeros (or roots) of the quadratic polynomial (or x-intercepts of the graph) and C is a scaling constant that needs to be determined.

Thanks!

- Math -
**Steve**, Tuesday, January 24, 2012 at 12:29amthe vertex is at (214.26,102.51)

So, y = C(x-214.26)^2 + k

102.51 = C(0)^2 + k

so, k = 102.51

y = C(x-214.26)^2 + 102.51

0 = C(432-214.26)^2 + 102.51

C = -0.002162

y = -0.002162(x-214.26)^2 + 102.51

y = -.002162x^2 + .92646x + 3.25831

y = -.002162(x+3.4885)(x-432)

- Math -
**HUNU**, Tuesday, January 24, 2012 at 9:21pmWhy are these poor models for a parabola, Where a ball starts a a certain point and then is hit to reach a maximum height (vertex) and then lands at a certain point

i. y = -0.002x(x - 437.1)

ii. y = -0.5x + 216x + 3

iii. y = -0.002x + 0.879x + 3.981

iv. y = -0.002x + 0.8732x - 3.981

Thanks!

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