If you do not consider air resistance, gravity causes a falling object to descend a distance of (9.8)t2 where t is the time in seconds. If a 16 pound bowling ball is dropped from the tallest building in the world, how many meters does it fall during the 4th and 5th seconds combined.

find the total distance in 5 seconds.

then find the total distance in 4 seconds.

subtract one from another.

I'd subtract the distance fallen in 3 seconds, leaving the combined total of seconds 4 and 5. :-)

To find the distance the bowling ball falls during the 4th and 5th seconds combined, we need to calculate the distance it falls during each of those seconds separately and then add them together.

According to the given equation, the distance fallen by an object in free fall, neglecting air resistance, is given by the formula: d = (9.8)t^2, where d is the distance in meters and t is the time in seconds.

Let's calculate the distance fallen during the 4th second: Plug in t = 4 seconds into the formula: d = (9.8)(4)^2 = 9.8 * 16 = 156.8 meters.

Now let's calculate the distance fallen during the 5th second: Plug in t = 5 seconds into the formula: d = (9.8)(5)^2 = 9.8 * 25 = 245 meters.

Finally, we add the distances fallen during the 4th and 5th seconds together: 156.8 + 245 = 401.8 meters.

Therefore, the bowling ball falls a total distance of 401.8 meters during the 4th and 5th seconds combined.