Wednesday

November 25, 2015
Posted by **theresa** on Monday, January 23, 2012 at 5:26pm.

- grade 8 math -
**Gavin**, Thursday, January 26, 2012 at 10:17pm72

- grade 8 math -
**y.**, Wednesday, June 18, 2014 at 5:36pm336

- grade 8 math -
**Staci**, Thursday, June 26, 2014 at 2:55pmOk if you have cars A B C D E F G H. Your options for the first three places are :

ABC, ABD, ABE, ABF, ABG, ABH

ACB, ACD, ACE, ACF, ACG, ACH

ADB, ADC, ADE, ADF, ADG, ADH

AEB, AEC, AED, AEF, AEG, AEH

AFB, AFC, AFD, AFE, AFG, AFH

AGB, AGC, AGD, AGE, AGF, AGH

AHB, AHC, AHD, AHE, AHF, AHG

6 x 7 = 42 options with car A in first place.

you can go through and do the same thing with each car in first place...

BAC, BAD, BAE..... HGD, HGE, HGF...

But to do it mathematically ~ 8 cars, 42 options with each car in first place.

42 x 8 = 336 different ways eight cars can finish a race in first, second and third place.