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March 25, 2017

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Find the surface area of a sphere with a circumference of 40 ft. Round to the nearest tenth.

  • Geometry - ,

    since
    C = 2πr, r = C/2π

    V = 4/3 π r^3 = 4/3 π (C/2π)^3 = C^3/6π^2 = 64000/6π^2

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