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posted by Ash on Monday, January 23, 2012 at 2:21pm.

Find the surface area of a sphere with a circumference of 40 ft. Round to the nearest tenth.

since C = 2πr, r = C/2π V = 4/3 π r^3 = 4/3 π (C/2π)^3 = C^3/6π^2 = 64000/6π^2

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