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March 2, 2015

March 2, 2015

Posted by **Amir** on Monday, January 23, 2012 at 1:39pm.

- Math -
**Amir**, Monday, January 23, 2012 at 2:01pmplease help

- Math -
**12-year-old-poet**, Monday, January 23, 2012 at 2:05pm(sinA/1+cosA)+(1+cosA/sinA) = 2cscA?

Work on LHS

sinA/(1+cosA)+(1+cosA)/sinA

=[sin^2A + (1 + cosA)^2]/[sinA(1 + cosA)]

=[sin^2A + 1 + 2cosA + cos^2A]/[sinA(1 + cosA)]

=[(sin^2A + cos^2A) + 1 + 2cosA]/[sinA(1 + cosA)]

=[1 + 1 + 2cosA]/[sinA(1 + cosA)]

=[2 + 2cosA]/[sinA(1 + cosA)]

=[2(1 + cosA)]/[sinA(1 + cosA)]

=2/sinA

=2(1/sinA)

=2cscA

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