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1/(1-sintheta) * 1/(1+sintheta) = sec^2theta

sec^2theta is the answer, it would be great if someone can do the steps for me. thank you.

  • Pre-Calculus -

    Left Side
    = 1/(1 - sinØ) * 1/(1+sinØ)
    = 1/((1-sinØ)(1+sinØ)
    = 1/(1-sin^2 Ø)
    = 1/cos^2 Ø
    = sec^2 Ø
    = Right Side

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