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February 1, 2015

February 1, 2015

Posted by **Amir** on Monday, January 23, 2012 at 10:28am.

2X^2 + 3XY - Y^2 + 1 = 0

- MATH -
**Reiny**, Monday, January 23, 2012 at 10:42amSo it does.

use substitution to solve ...

2x^2 + 3x(x+4) - (x+4)^2 + 1 = 0

2x^2 + 3x^2 + 12x - x^2 - 8x - 16 + 1 = 0

4x^2 + 4x - 15 = 0

(2x-3)(2x+5) = 0

I am sure you can finish it.

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