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posted by Amir on Monday, January 23, 2012 at 10:01am.
prove that (cotx+tanx)(cotx-tanx) = 1/(sin^2 x) - 1/(cos^x)
cot^2 - tan^2 cos^2/sin^2 - sin^2/cos^2 (1 - sin^2)/sin^2 - (1-cos^2)/cos^2 1/sin^2 - 1 - 1/cos^2 + 1 1/sin^2 - 1/cos^2
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