Posted by **ME** on Monday, January 23, 2012 at 12:27am.

Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the line x = 6.

y = 6 − x

y = 0

y = 5

x = 0

- calculus -
**Steve**, Monday, January 23, 2012 at 10:29am
You can use shells:

The region has to be broken up into the constant-height region where 0<=x<=1 and the slanting region where 1<=x<=6:

V = 2pi*Int(r*5 dx)[0,1] + 2pi*Int(rh dx)[1,6]

where r = 6-x

h = 6-x

= 138 2/3 pi

Or, using discs,

V = pi*Int(6^2 - y^2) dy[0,5]

= 138 2/3 pi

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