The compound potassium carbonate is a strong electrolyte. Write the reaction when potassium carbonate is put into water
K2CO3 ==> 2K^+ + CO3^2-
Both K^+ and CO3^2- are hydrated but this generally is not shown. I assume the idea here is to know that strong electrolytes ionize 100%.
Well, when potassium carbonate goes for a swim in water, it breaks down into its ions with a splash! The reaction can be written as:
K2CO3 + H2O → 2K+ + CO3^2- + H2O
So, we end up with two positively charged potassium ions (K+), one carbonate ion (CO3^2-), and some happy little water molecules (H2O) floating around having a good time. It's quite the electrifying experience, if you ask me!
When potassium carbonate is put into water, it dissociates into its respective ions. The reaction can be represented as:
K2CO3 (s) + H2O (l) → 2K+ (aq) + CO3^2- (aq)
In this reaction, potassium carbonate (K2CO3) reacts with water (H2O) to form aqueous potassium ions (K+) and carbonate ions (CO3^2-). This dissociation occurs due to the polar nature of water molecules, which attracts and separates the ions of the potassium carbonate compound.
To write the reaction when potassium carbonate (K2CO3) is put into water, we need to consider how the compound dissociates into its constituent ions in an aqueous solution.
Potassium carbonate is an ionic compound composed of potassium ions (K+) and carbonate ions (CO3²-). When it is placed in water, the polar water molecules surround and interact with the ions, breaking them apart or dissociating them.
The dissociation reaction of potassium carbonate in water can be represented as follows:
K2CO3(s) + H2O(l) → 2K+(aq) + CO3²-(aq)
In this reaction, the solid potassium carbonate (K2CO3) interacts with the liquid water (H2O), resulting in the formation of potassium ions (K+) and carbonate ions (CO3²-) in the aqueous solution.
It's important to note that, as a strong electrolyte, potassium carbonate completely dissociates into its ions when dissolved in water, allowing the resulting solution to conduct electricity efficiently.