posted by lynn on .
How much aluminum nitrate can be found
when 12 g of aluminum react with lead(II)
Answer in units of mol
2Al + 3Pb(NO3)2 ==> 2Al(NO3)3 + 3Pb
1. Convert 12 g Al to moles. moles = g/molar mass
2. Using the coefficients in the balanced equation, convert mol Al to moles Al(NO3)3
3. Convert moles Al(NO3)3 to g. g = moles x molar mass.