calculate the energy, in joules and calories
required to heat 25.0g of water form 12.5 deg. celcius to 25.7 deg. celcius i know the answer just need to see how to do it especially the calories
chemistry - DrBob222, Sunday, January 22, 2012 at 7:20pm
q = mass x specific heat water x delta T
q = 25.0g x 1 cal/g*C x (25.7-12.5) = ?
For joules, substitute 4.18 J/g*C for 1 cal/g*C