Posted by **Hannah** on Sunday, January 22, 2012 at 2:39pm.

A cup of teat containing 400g of liquid at 20 degrees celsius was heated. If 58.5 kj of heat was absorbed by the tea, what would the final temperature be? Assume that the specific heat of the tea is the same as that of water (4.18).

I am not sure how to start this problem.

Chemistry - DrBob222, Saturday, January 21, 2012 at 6:34pm

You know the specific heat formula of

q = mass x specific heat x (Tfinal-Tinitial). Start there. Substitute and solve for Tf

I did 400/58.5 (4.18) and got 28.6 degrees celsius which is one of the answer choices. Was I suppose to use the 20 degrees that was stated in the problem?

- Chemistry -
**DrBob222**, Sunday, January 22, 2012 at 3:52pm
Of course. I don't understand why you are having so much trouble with this. I gave you the equation and it's just a case of substituting the numbers and solving for Tf = Tfinal.

q = mass x specific heat x (Tf-Ti)

58,500 = 400 x 4.18 x (Tf-20)

Solve for Tf.

- Chemistry -
**Hannah**, Sunday, January 22, 2012 at 4:37pm
I am having trouble with getting Tf by itself thats all.

- Chemistry -
**DrBob222**, Sunday, January 22, 2012 at 4:48pm
OK. Algebra is your problem. This is like

500 = 4 x (T-20)

500 = 4*T - 4*20

500 = 4T - 80

500+80 = 4T

580/4 = T

T = 145

58,500 = 400 x 4.18 x (Tf-20)

58,500 = (400*4.18*T) - (400*4.18*20)

58,500 = 1672.76Tf - 33440

I will let you you finish?

- Chemistry -
**Hannah**, Sunday, January 22, 2012 at 5:13pm
Ok I got 54.9 which would round to 55 which is an answer choice that they gave me.

- Chemistry -
**MANISH**, Saturday, September 22, 2012 at 1:17am
बोर परमाणु माडल के चार अभिग्रहित लिखिएँ

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