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December 18, 2014

December 18, 2014

Posted by **Hannah** on Sunday, January 22, 2012 at 2:39pm.

I am not sure how to start this problem.

Chemistry - DrBob222, Saturday, January 21, 2012 at 6:34pm

You know the specific heat formula of

q = mass x specific heat x (Tfinal-Tinitial). Start there. Substitute and solve for Tf

I did 400/58.5 (4.18) and got 28.6 degrees celsius which is one of the answer choices. Was I suppose to use the 20 degrees that was stated in the problem?

- Chemistry -
**DrBob222**, Sunday, January 22, 2012 at 3:52pmOf course. I don't understand why you are having so much trouble with this. I gave you the equation and it's just a case of substituting the numbers and solving for Tf = Tfinal.

q = mass x specific heat x (Tf-Ti)

58,500 = 400 x 4.18 x (Tf-20)

Solve for Tf.

- Chemistry -
**Hannah**, Sunday, January 22, 2012 at 4:37pmI am having trouble with getting Tf by itself thats all.

- Chemistry -
**DrBob222**, Sunday, January 22, 2012 at 4:48pmOK. Algebra is your problem. This is like

500 = 4 x (T-20)

500 = 4*T - 4*20

500 = 4T - 80

500+80 = 4T

580/4 = T

T = 145

58,500 = 400 x 4.18 x (Tf-20)

58,500 = (400*4.18*T) - (400*4.18*20)

58,500 = 1672.76Tf - 33440

I will let you you finish?

- Chemistry -
**Hannah**, Sunday, January 22, 2012 at 5:13pmOk I got 54.9 which would round to 55 which is an answer choice that they gave me.

- Chemistry -
**MANISH**, Saturday, September 22, 2012 at 1:17amबोर परमाणु माडल के चार अभिग्रहित लिखिएँ

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