D is the set of whole numbers less than 3.
(1 point)
D = {0,1,2,3,4,5}; D = {x is a whole number, x < 3}
D = {0,1}; D = {x | x < 3}
D = {0,1,2}; D = {x | x is a whole number, x < 3}
D = {0,1,2,3,4,5,6,7}; D = {x < 3}
of the q (4-3y)3
D = {0,1,2}; D = {x | x is a whole number, x < 3}
Because D is the set of whole numbers less than 3, we can only include 0, 1, and 2 in the set. And we can write it using set-builder notation as {x | x is a whole number, x < 3}.
D = {0,1,2}; D = {x | x is a whole number, x < 3}
The correct answer is:
D = {0,1,2}; D = {x | x is a whole number, x < 3}
To understand why, let's break down the options:
Option 1: D = {0,1,2,3,4,5}; D = {x is a whole number, x < 3}
This option includes numbers that are greater than or equal to 3, which contradicts the statement "whole numbers less than 3." So, option 1 is incorrect.
Option 2: D = {0,1}; D = {x | x < 3}
This option correctly identifies the whole numbers less than 3 (0 and 1). However, it does not include the number 2, which is also a whole number less than 3. Therefore, option 2 is incorrect.
Option 3: D = {0,1,2}; D = {x | x is a whole number, x < 3}
This option correctly identifies the whole numbers less than 3 (0, 1, and 2). Additionally, it explicitly states that the set consists of whole numbers and that each number is less than 3. Therefore, option 3 is correct.
Option 4: D = {0,1,2,3,4,5,6,7}; D = {x < 3}
This option includes numbers that are greater than or equal to 3, which contradicts the statement "whole numbers less than 3." So, option 4 is incorrect.
Therefore, the correct answer is:
D = {0,1,2}; D = {x | x is a whole number, x < 3}