Posted by **Mary** on Sunday, January 22, 2012 at 10:57am.

a farmer wants to put a fence around a rectangular field and then divide the field into three rectangular plots by placing two fences parallel to one of the sides. if the farmer can only afford 1000 yards of fencing, what dimensions will give the maximum rectangular area?

- Math -
**Reiny**, Sunday, January 22, 2012 at 1:14pm
Make a sketch

let the length of the whole field be y yds

let each divider line be x yds

so 2y + 4x = 1000

y = 500 - 2x

area = xy

= x(500-2x)

= 500x - 2x^2

I will assume you are taking Calculus, if not you will have to complete the square on the above

d(area)/dx = 500 - 4x = 0 for a max area

4x=500

x = 125

then y = 250

The whole length should be 250 yrd , and each smaller pen should be 125 yrds wide.

max area = 125(250) = 31250 yds^2

- Math -
**Jesus**, Tuesday, June 23, 2015 at 3:19pm
Nigga

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