Tuesday
March 28, 2017

Post a New Question

Posted by on .

Please show me how to solve:

Doctors can use radioactive iodine to treat some forms of cancer. The half-life of iodine - 131 is 8 days. A patient receives a treatment of 12 millicuries of iodine - 131. (A mullicurie is a unit of radioactivity.) How much iodine - 131 remains in the patient 16 days later?

  • Math - ,

    amount = 12 (1/2)^(168)
    = 12(1/2)^2 = 3 millicuries

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question