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December 21, 2014

December 21, 2014

Posted by **lily** on Sunday, January 22, 2012 at 2:23am.

- Math 543 -
**Mario**, Sunday, January 22, 2012 at 2:35am56

- Math 543 -
**claudia**, Sunday, January 22, 2012 at 2:48amhow did you solve

- Math 543 -
**Reiny**, Sunday, January 22, 2012 at 9:08amso we have

1+3+5+7+... = 3136

let the number of terms of this AS be n

(n/2)(2a +(n-1)d) = Sum(n)

So we have a=1, d=2 , and n = ?

(n/2)(2 + (n-1)2) = 3136

times 2 ....

n(2 + 2n - 2) = 6272

2n^2 = 6272

n^2 = 3136

n = ± 56 , but n has to be a positive whole number,

there are 56 terms

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