Posted by **lily** on Sunday, January 22, 2012 at 2:23am.

The number 3136 is the sum of the first how many odd whole numbers?

- Math 543 -
**Mario**, Sunday, January 22, 2012 at 2:35am
56

- Math 543 -
**claudia**, Sunday, January 22, 2012 at 2:48am
how did you solve

- Math 543 -
**Reiny**, Sunday, January 22, 2012 at 9:08am
so we have

1+3+5+7+... = 3136

let the number of terms of this AS be n

(n/2)(2a +(n-1)d) = Sum(n)

So we have a=1, d=2 , and n = ?

(n/2)(2 + (n-1)2) = 3136

times 2 ....

n(2 + 2n - 2) = 6272

2n^2 = 6272

n^2 = 3136

n = ± 56 , but n has to be a positive whole number,

there are 56 terms

## Answer this Question

## Related Questions

- Math 543 - The number 3136 is the sum of the first how many odd whole numbers?
- SUMS? - what is the sum of the first towo odd numbers? what s the sum of the ...
- Math - Nine consecutive odd whole numbers sum to 243. Find the sum if the first...
- math - If the first of 1000 consecutive whole numbers is odd, their sum must be ...
- math - The sum of the first n odd number is n^2. The sum of the first 30 odd ...
- Math - Sum the first two odd numbers, then the first three, the first four, and ...
- Mathematics - Cardinal Number - Hi, This is a really easy question. I think I am...
- Math 130 - Sum the first two odd numbers, then the first three, the first four...
- Math - Find the sum of the first 35 consecutive odd numbers. What is the sum of ...
- Math! Please check! - Consider the statement: If two whole numbers are even, ...

More Related Questions