a ball of mass 8kg falls from rest from a height of 100m.neglecting air resistance,calculate its total energy after falling a distance of 40m
This question is just straight forward. We know that it all about EK and EP but it common sense to answer this question. It says
8kg falls from rest and
the height is 100 m
Neglect air resistance and calculate the total energy after falling a distance of 40 m.
Fall from rest _ 8*100= 800.
Total energy after falling is 40 *100=4000.
Then you add the both answers together, that is falling from rest * total energy after falling, which is; 800 + 4000 = 4800joules...
Fall from rest is 8* 100=800
Total energy after falling is 40*100= 4000. Then u add both answer together 4000*800=4800joule
4,800j
The simple answer to this question is the potential energy of 8kg at (100-40)m which is 60m above the ground.
Answer= 8kg * 10m/s² * 60m
Which gives us 4800j..
@ rest no g then it is =8*100 which will give you 800
Then another work (energy) is done through 40m =100*40
=4000
All together 4800, is correct
Total energy after falling a distance of 40m is simply the sum of the energy, when it fell from a height of 100m and 40m. Neglecting air resistance we have first energy obtained to 8*100=800 and second energy obtained to 40*100=4000 (i.e work done through 40m).sum of both energies will happen to be 4800joules.
From rest = 8×100=800
After falling = 40 ×100=4000
Total energy = 4000 + 800 = 4800 joules
I don't understand how to arrive at the answer
I don't know how we arrive at
the answer