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January 29, 2015

January 29, 2015

Posted by **Akash** on Sunday, January 22, 2012 at 1:07am.

y = ae^3x + be^-2x with dy/dx = 3ae^3x - 2be^-2x

- 12th Grade Calculus -
**Reiny**, Sunday, January 22, 2012 at 9:40amStrange,

you are taking Calculus and ask how to multiply

(ae^(3x) + be^(-2x))(3ae^(3x) - 2be^(-2x) ) ??

= 3a^2 e^(6x) - 2ab + 3ab - 2b^2 e^(-4x)

= 3a^2 e^(6x) + ab - 2b^2 e^(-4x)

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