Posted by Akash on Sunday, January 22, 2012 at 1:07am.
Strange,
you are taking Calculus and ask how to multiply
(ae^(3x) + be^(-2x))(3ae^(3x) - 2be^(-2x) ) ??
= 3a^2 e^(6x) - 2ab + 3ab - 2b^2 e^(-4x)
= 3a^2 e^(6x) + ab - 2b^2 e^(-4x)
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