Posted by **Summer** on Sunday, January 22, 2012 at 12:11am.

I'm doing online chemistry homework, and the site keeps telling me I have the wrong answer, but I'm not sure what I'm doing wrong. please help?

What is the pH of a 0.089M solution of phosphorous acid (H2PHO3) in water? The value of Ka1 for H2PHO3 is 1.600 E-2 and the value of Ka2 is 7.000 E-7.

H2PHO3 + HOH --> HPHO3^-1 + HeO^+1

0.089M............0..........0

-x...............x..........x

.089-x...........x..........x

1.600E-2=x^2/.089-x

I used the 5% rule, so x= 3.774E-2

and then since Ka2 is so small, is it insignificant? I thought it was, so I went ahead and calculated pH.

pH=-Log(3.774E-2)

pH=1.42

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