Posted by DJ on Saturday, January 21, 2012 at 8:34pm.
Let's say we want to eliminate 's'
So multiply 5 to the first equation
and multiply 3 to the second equation
25r - 15s = 80
9r + 15s = 90
use the elimination method by adding those two equation -15s and 15s cancels out
34r = 170
Then r = 5
alberga - 3r-5s=-4 5r+3s=16 elimination method
algebra - how do you solve this problem by elimination method 5r-3s=14 3r+5s=56
math elimination method - elimination method really confuses me. solve by ...
Algebra - Solve by elimination method.. 3r - 5s = 14 5r + 3s = 46.
Algebra - please help me!! Solve by elimination method: 3r - 5s = 6 5r + 3s = 44...
Math116 - Solve by elimination 5r-3s=13 3r+5s=69
Math - Solve by the elimination method. 5r-3s=2 3r 5s =42 r=-40 is this right. ...
algebra - elimination method 3r-5s=-14 5r+35-56
Elimination method - Solve by the elimination method. Is there a solution? 2r-5s...
Math - using the elimination method ...does this problem have an answer?...if so...
For Further Reading