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December 20, 2014

December 20, 2014

Posted by **DJ** on Saturday, January 21, 2012 at 8:34pm.

using the elimination method

5r-3s=16

3r+5s=30

- math problem -
**yuuka**, Saturday, January 21, 2012 at 11:21pmLet's say we want to eliminate 's'

So multiply 5 to the first equation

and multiply 3 to the second equation

we get:

25r - 15s = 80

9r + 15s = 90

use the elimination method by adding those two equation -15s and 15s cancels out

we get:

34r = 170

Then r = 5

- math problem -
**Anonymous**, Wednesday, April 18, 2012 at 1:15pm2c+3d+7-5c

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