very confused could someone help me with this
using the elimination method
5r-3s=16
3r+5s=30
Let's say we want to eliminate 's'
So multiply 5 to the first equation
and multiply 3 to the second equation
we get:
25r - 15s = 80
9r + 15s = 90
use the elimination method by adding those two equation -15s and 15s cancels out
we get:
34r = 170
Then r = 5
2c+3d+7-5c
Of course! I'd be happy to help you solve this system of equations using the elimination method.
Step 1: Multiply the first equation by 3 and the second equation by 5 to eliminate the "r" term. This gives:
15r - 9s = 48 (Equation A)
15r + 25s = 150 (Equation B)
Step 2: Now we can eliminate the "r" term by subtracting Equation A from Equation B. The "r" term cancels out, leaving us with only the "s" term:
(15r + 25s) - (15r - 9s) = 150 - 48
34s = 102
Step 3: Divide both sides of the equation by 34 to solve for "s":
s = 102 / 34
s = 3
Step 4: Substitute the value of "s" back into either Equation A or B to solve for "r". Let's use Equation A:
5r - 3s = 16
5r - 3(3) = 16
5r - 9 = 16
5r = 16 + 9
5r = 25
Step 5: Divide both sides of the equation by 5 to solve for "r":
r = 25 / 5
r = 5
So, the solution to the system of equations is r = 5 and s = 3.