math problem
posted by DJ on .
very confused could someone help me with this
using the elimination method
5r3s=16
3r+5s=30

Let's say we want to eliminate 's'
So multiply 5 to the first equation
and multiply 3 to the second equation
we get:
25r  15s = 80
9r + 15s = 90
use the elimination method by adding those two equation 15s and 15s cancels out
we get:
34r = 170
Then r = 5 
2c+3d+75c